Supplemental Material
Standing Waves: A key concept in this book is an unfamiliar type of “standing wave”, which appears in Chapter 17 and Chapter 20. It’s relation to guitar strings’ standing waves is sketchily depicted in Figure 41. The difference between this type of standing wave and more familiar standing waves is described in this post, along with animations (and some further links to the math background) on this page; see also additional explanation and animations in this follow-up post as well as this one.
FAQ [click on the question to see the answer]
Q: If a stationary electron is a standing wave, what holds the electron’s edges in place, in analogy to the way a guitar string is held at its edges, or the way a standing wave in a bathtub is constrained by the walls of the tub?
Nothing is needed to “hold the edges”, because the electron field and its standing waves have unfamiliar properties that are different from those found for the standing waves of guitar strings. This is explained in this post, along with animations (and some further links to the math background) on this page; see also this follow-up post with more animations and clarifications.
Q: Regarding note 6 of chapter 17: why would photons be emitted with any directionality? Should one not be emitted spherically into all “space” and its eventually future effective effect depend on the eventual wave function collapse when absorbed?
This is subtle, and requires a deeper understanding of how quantum physics really works well beyond what I discussed in the book.
In the question, the recoil of the atom is being ignored; implicitly the atom is assumed to have infinite mass and so doesn’t move. But that’s not the case. When it’s mass is finite, it’s not true that the photon is emitted spherically, or at least one has to be extremely careful about such a statement, because the photon’s motion is correlated with the atom’s.
To see this, consider the decay of a stationary Higgs boson to two photons. Are they emitted spherically? In a sense, yes; the Higgs boson has no intrinsic directionality, so the photons can go in any direction. And yet, when measured, the two photons are always in opposite directions, a requirement of momentum conservation. How can this be? The point is that the wave function for the two photon system is spherically symmetric, but not the individual photons. The direction the photons go is completely random, but they will always be back-to-back; the probability that they are not is zero.
Similarly, the photon-atom pair may have a spherically symmetric wave function (if the atom is simple enough), and so the photon may go in any direction; but the atom always goes in the opposite direction, showing that the system was not, in fact, describing a spherically symmetric photon. Instead it was a spherically symmetric wave function describing a photon going one way and an atom going the other way.
Even this isn’t quite right, because so far I’ve made an implicit assumption: that we are measuring the outgoing photons with a detector that is localized in angle. We wouldn’t see this effect if we used a spherically symmetric detector; then it would indeed absorb a spherically symmetric photon, and the atom’s direction of motion would remain completely uncertain. This fact is also correctly captured by the wave function of the photon-atom system.
Endnotes
Note 1: The W boson’s lifetime and mass
- Quote: Thus, for each elementary field of nature, there’s a corresponding type of wavicle, with a definite rest mass. For the electron field, there are electrons, every one of which has a rest mass identical to that of all the others. For the electromagnetic field, there are photons, all with zero rest mass. The W field >has W bosons, each of which has the same mass.
- Endnote: Strictly speaking, this is true to within the requirements of the cosmic certainty limit.
- Discussion:
I have stated that all W bosons have the same rest mass. But thanks to quantum physics, this isn’t quite true.
A W boson has a finite lifetime — on average, it exists for just 3×10−25 seconds. Quantum physics, via Heisenberg’s uncertainty principle, then makes it impossible to define its energy precisely. As a result, if you measure many W bosons (by studying the objects they decay to), you’ll find their rest masses are very similar but not exactly the same.
The same is true for the Z boson. Because it has some very simple decay modes, a measurement of its mass is much more precise, and we can see and understand the effect more immediately. A measurement of the masses of a large number of Z bosons shows the result in the figure below. (The measurement is more precise that the width of the spike.) The cause of the width of the spike is just what I described — the finite lifetime reduces the time that the the particle may live, making the time of its demise more certain. This in turn introduces uncertainty in its energy, including its internal energy, which translates into uncertainty in its rest mass.
Quantitatively, the uncertainty in the Z boson rest massis related to its lifetime
via Planck’s constant
as follows:
The uncertainty in the Higgs boson’s rest mass is 1/500 that of the Z boson’s rest mass, and its lifetime correspondingly more than 500 times longer. This is thanks to details of the Higgs field’s interactions, as compared to the simpler interactions of the Z field (see Chapters 21-22.)
![](https://profmattstrassler.com/wp-content/uploads/2024/03/image-21.png)
Note 2: The proton’s size
- Quote: This difference between electrons and protons confirms that the latter has a measurable size, while the former (up to now) apparently does not.
- Endnote: More technically, what one looks for is proof that the internals of the proton can themselves start vibrating, like the sloshing of milk in a shaken container; this is called an excited state of the proton. There are simpler but more subtle methods that can measure the proton’s size even more easily.
- Discussion
Note 6: Absorption and emission of light
- Quote: When the atoms in your body absorb light, each does so one photon at a time.
- Endnote: When a photon is absorbed, the photon strikes the atom and disappears, while its energy is taken up by the atom. Emission of light is the exact reverse; the atom gives up some excess energy and transfers it to a spontaneously created photon.
- Discussion (coming soon)
Note 7: Breadth of a stationary electron
- Quote: “That gives us the best image I know of: a high-frequency low-amplitude extended standing wave stretching off in all directions.”
- Endnote: How broad does this standing wave’s crest really need to be to count as a “stationary” electron? For our purposes, a lot wider than an atom but narrower than a human. If it’s a millimeter across or more, any associated uncertainty in its motion has slowed below walking speed, which is far less than needed for a precise rest mass measurement.
- Discussion: I addressed this issue recently in this post (see this page for animations) and in this post (which also has animations).