- Quote: Ironically, most particle physicists don’t use either of these two simple interpretations of the relativity formula. We use a third one!
- Endnote: Taking E to be total energy and m to be rest mass, we view E = m[c2] as true only for stationary objects. Otherwise E > m[c2]; in words, the total energy of a moving object always exceeds its internal energy (by an amount that can be easily expressed in terms of the quantity called momentum.)
We particle physicists write
where p is momentum. In terms of the object’s speed v, we don’t use Newton’s formula for momentum, p = mv, but instead we use an Einsteinian version,
Note: this is not the same as Newton’s formula p = mv, because we particle physicists use equation (1), which says that for a moving object E is NOT equal to mc2 ! [Got to keep on your toes, here!]
Instead, combining equations (1) and (2), we find
Bringing the second term to the left-hand side and factoring.
Solving for E gives
a formula which appears in endnote 7 of this chapter and the ensuing discussion.
Let’s return now to equation (1). For a moving object, v is non-zero, so p is non-zero too, and p2 is positive. Therefore
and thus, taking the square root of both sides (and remembering both motion energy and mass are always positive), we find that
for a moving object. This can also be seen from equation (3); if v is non-zero, then (v/c)2 is positive but less than 1, so the square root is less than 1, and one over the square root is greater than 1.
Meanwhile for a stationary object, v and p are zero, so returning to equation (1) and taking the square root, or simply using equation (3), we find
[See also this article in which I discuss and give intuition as to how Einstein’s formulas were a sensible generalization of Newton’s formulas.]